Respuesta :
Answer: The percent yield of water is 84.72 %
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] Â Â Â .....(1)
For methane:
Given mass of methane= 0.16 g
Molar mass of methane = 16 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of methane}=\frac{0.16g}{16g/mol}=0.01mol[/tex]
For oxygen gas:
Given mass of oxygen gas = 0.25 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{0.25g}{32g/mol}=0.008mol[/tex]
The chemical equation for the reaction is
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of oxygen gas reacts with 1 mole of methane
So, 0.008 moles of oxygen gas will react with = [tex]\frac{1}{2}\times 0.008=0.004mol[/tex] of methane
As, given amount of methane is more than the required amount. So, it is considered as an excess reagent.
Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of oxygen gas produces = 2 moles of water
So, 0.008 moles of oxygen gas will produce = [tex]\frac{2}{2}\times 0.008=0.008moles[/tex] of water
Mass of water=[tex]moles\times {\text{Molar Mass}}=0.008\times 18=0.144g[/tex]
To calculate the percentage yield of titanium (IV) chloride, we use the equation:
[tex]\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]
Experimental yield of water = 0.122
Theoretical yield of water = 0.144 g
Putting values in above equation, we get:
[tex]\%\text{ yield of water}=\frac{0.122g}{0.144g}\times 100\\\\\% \text{yield of water}=84.72\%[/tex]
Hence, the percent yield of water is 84.72%.
