Show the mechanism for the following reaction conducted at –5 °C in CCl4: cyclohexene bromine yields a dibromocyclohexane Draw wedge-and-dash bond stereochemical structures – including H atoms at a chirality center – and include charges, electrons, and curved arrows. Details count. Draw one enantiomer only for any racemates.

In the first step, a cyclic structure with a positive bromine is formed. The bromine shares the positive charge with the two carbons that it is bonded to, so the carbons are partially positive.

The second bromine atom then attacks the carbon center, coming in from below the first bromine atom ("backside attack") where the antibonding orbital of the second bromine atom is.

The stereochemistry of the mechanism causes the final product to be an anti-dibromocyclohexane.

kasliwalalvi24 kasliwalalvi24 · Answer 2 · 2021-10-25T08:10:46+02:00

Tetrachloromethane is an organic molecule having functional group of halogen. The reaction between cyclohexane and bromine will yield dibromocyclohexane. The stereochemistry of enantiomers makes the final product anti-dibromocyclohexane.

Given below is the attachment of reaction of cyclohexane and bromine.

The cyclohexane is a cyclic structure with the chemical formula C[tex]_6[/tex]H[tex]_{12}[/tex]. The structure is formed in the presence of positive bromine ion. The bromine shares the positive charge, making the carbons in the ring partially positive.

Now, the second atom of bromine will attach the carbon centre from the back side, the position where antibonding orbitals of second bromine are present. Therefore, the stereochemistry of the cyclohexane will result in the formation of dibromocyclohexane.

To know more about cyclic structures, refer to the following link:

https://brainly.com/question/16259675?referrer=searchResults