Answer:
[tex]x = 4.76 \times 10^{-3} miles[/tex]
Explanation:
Since two runners are moving towards each other and meet at distance "x" from flag pole then the distance covered by Runner A is given as
[tex]d_1 = (4.4 + x) miles[/tex]
also we have distance moved by runner B is
[tex]d_2 = (3 - x) miles[/tex]
now if they both meet at this position
so the time taken by both runners to reach this position must be same
so we will have
[tex]t = \frac{d_1}{v_1} = \frac{d_2}{v_2}[/tex]
[tex]\frac{4.4 + x}{7.5} = \frac{3 - x}{5.1}[/tex]
[tex]4.4 + x = 1.47(3 - x)[/tex]
[tex](1.47 + 1)x = 0.0118 miles[/tex]
[tex]x = 4.76 \times 10^{-3} miles[/tex]
