Answer: 2 moles of water.
Explanation:
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
Given moles:
moles of oxygen = 2.5
moles of [tex]C_3H_8[/tex] = 4.6
According to stoichiometry:
5 moles of oxygen reacts with = 1 mole of propane
Thus 2.5 moles of oxygen will react with = [tex]\frac{1}{5}\times 2.5=0.5[/tex] moles of oxygen
Thus propane is the limiting reagent as it limits the formation of products and oxygen is the excess reagent.
As 1 mole of propane produce = 4 moles of water
0.5 mole of propane will produce =[tex]\frac{4}{1}\times 0.5=2moles[/tex] of water
Thus 2 moles of water are produced.
