Answer:
Step-by-step explanation:
Given that a population has mean as 56 and std deviation as 16.
The above are population parameters.
Whenever random samples are drawn for large size, by central limit theorem we have the sample mean will follow a normal distribution with mean = population mean and std error = std deviation/sqrt of n
Hence here sample bar will be normal with
Mean of x bar = [tex]56[/tex]
Std error of x bar = [tex]\frac{16}{\sqrt{27} } =3.079[/tex]
