tinkssong1974
contestada

The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 192 feet, what is the area of the garden in square feet?

Respuesta :

yoooojefehf

Answer:The sides of the garden are x and x + 9

The perimeter of a rectangle is 2x + 2y (where x is the width and y is the length)

So your equation is:

2x + 2(x+9) = 194

Distribute the 2s:

2x + 2x + 18 = 194

Simplify:

4x + 18 = 194

Combine like terms:

4x = 176

Solve for x:

x = 44

So the sides are 44 and 53

Area = xy so multiply to get your answer.

Step-by-step explanation:

Answer:

The area of the garden is 2332 sq feet.

Step-by-step explanation:

Step 1:

Let us assume L be the width and L+8 length of the rectangular garden and also P be perimeter.

Step 2:

We got the equation from the given data.

P = 2.(2L + 8) = 4L+ 16 =192.

Divide by four on both sides of equation to yield.

(4L + 16) / 4 =192/4

L + 4 = 48

L = 44

Step 3:

Area is length time’s width for a rectangle.

A = L(L+8)

Step 4:

Substituting L=44 and L=53 into A yields

A = (44).(53) = 2332

Area= 2332 Square Feet.

Otras preguntas

Q&A Education