Answer:
5 N
Explanation:
Force, F1 = 3 N at 30° above the horizontal
F2 = 4 N downwards
Write the forces in vector notation
[tex]\overrightarrow{F_{1}}=3\left ( Cos30\widehat{i}+Sin30\widehat{j} \right )[/tex]
[tex]\overrightarrow{F_{1}}=2.59\widehat{i}+1.5\widehat{j} N[/tex]
[tex]\overrightarrow{F_{2}}=-4\widehat{k} N[/tex]
the resultant force
[tex]\overrightarrow{F}} = \overrightarrow{F_{1}}+\overrightarrow{F_{2}}[/tex]
[tex]\overrightarrow{F}} = 2.594\widehat{i}+1.5\widehat{j}-4\widehat{k} N[/tex]
The magnitude of resultant force is
F = [tex]\sqrt{\left ( 2.59 \right )^{2}+\left ( 1.5 \right )^{2}+\left ( -4 \right )^{2}}[/tex]
F = 5 N
