Someone please help me with this equation. Or at least explain it to me so I know how to do it. Thank you!
[tex]\huge\boxed{12x-4y=-3}[/tex]
Standard form is [tex]ax+by=c[/tex], where [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] are real numbers. The requirements vary a little bit from textbook to textbook, but I will follow the most common rules.
We are starting off with an equation in slope-intercept form. [tex]y=3x+\frac{3}{4}[/tex]
Subtract [tex]3x[/tex] from both sides. [tex]-3x+y=\frac{3}{4}[/tex]
Multiply both sides of the equation by [tex]4[/tex] to get rid of the fraction.
Multiply both sides of the equation by [tex]-1[/tex]. [tex]\boxed{12x-4y=-3}[/tex]