If $945 is invested at an interest rate of 4% per year and is compounded continuously, how much will the investment be worth in 10 years?


Use the continuous compound interest formula A = Pert.


A. $947

B. $984

C. $1,028

D. $1,410

Respuesta :

Answer:

Option D [tex]\$1,410[/tex]  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

[tex]A=P(e)^{rt}[/tex]  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

[tex]t=10\ years\\ P=\$945\\ r=0.04[/tex]  

substitute in the formula above  

[tex]A=945(e)^{0.04*10}[/tex]  

[tex]A=945(e)^{0.4}[/tex]  

[tex]A=\$1,410[/tex]  

The correct option is D which is ''the investment after 10 years is worth $1,410''.

Given

If $945 is invested at an interest rate of 4% per year and is compounded continuously.

What is formula is used to find continuous compound interest?

The formula is used to find continuous compound interest is;

[tex]\rm A = P(e)^{rt}[/tex]

Where p is the principal amount of money invested.

r is the rate of interest, t is the time of investment, A is the final amount invested value, and e is the exponential term.

Substitute all the values in the formula;

[tex]\rm A = P(e)^{rt}\\\\A = 945 \times (e)^{0.04 \times 10}\\\\A = 945 \times e^{0.4}\\\\A = 945 \times 1.49\\\\A= 1410[/tex]

Hence, the investment after 10 years is worth $1,410.

To know more about Compound interest click the link given below.

https://brainly.com/question/25857212

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