Respuesta :
Answer: The larger number be 61.
Step-by-step explanation:
Let the second number be 'x'.
Let the first number be 42+x
Average of two numbers = 40
According to question,
[tex]\dfrac{x+42+x}{2}=40\\\\\dfrac{2x+42}{2}=40\\\\2x+42=80\\\\2x=80-42\\\\2x=38\\\\x=\dfrac{38}{2}\\\\x=19[/tex]
So, the larger number of the two numbers i.e the first number is
[tex]42+x\\\\=42+19\\\\=61[/tex]
Hence, the larger number be 61.
Answer:
largest of the two number is 61
Step-by-step explanation:
given,
one number is 42 more that the second number
and average is equal to 40.
let as assume first number be x
so the second no becomes = x + 42
average of the two numbers = 40
[tex]\dfrac{x+42+x}{2}=40\\2x+42=80\\x=19[/tex]
so the first number is 19
second number will be equal to 19 + 42 = 61
hence the largest of the two number is 61
