Answer: The molarity of NaOH solution is 1.03 M.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of KHP = 2.48 g
Molar mass of KHP = 204.22 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of KHP}=\frac{2.48g}{204.22g/mol}=0.012mol[/tex]
The chemical reaction for the formation of chromium oxide follows the equation:
[tex]KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)[/tex]
By Stoichiometry of the reaction:
1 mole of KHP reacts with 1 mole of NaOH.
So, 0.012 moles of KHP will react with = [tex]\frac{1}{1}\times 0.021=0.021mol[/tex] of NaOH.
To calculate the molarity of NaOH, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
We are given:
Moles of NaOH = 0.021 moles
Volume of solution = 20.4 mL = 0.0204L (Conversion factor: 1L = 1000 mL)
Putting values in above equation, we get:
[tex]\text{Molarity of NaOH }=\frac{0.021mol}{0.0204L}=1.03M[/tex]
Hence, the molarity of NaOH solution is 1.03 M.
Answer:
The molarity of NaOH solution is 1.03 M.
Explanation:
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