Answer: The number of moles of weak acid is [tex]4.24\times 10^{-3}[/tex] moles.
Explanation:
To calculate the moles of KOH, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}[/tex]
We are given:
Volume of solution = 43.81 mL = 0.04381 L Â Â Â (Conversion factor: 1L = 1000 mL)
Molarity of the solution = 0.0969 moles/ L
Putting values in above equation, we get:
[tex]0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol[/tex]
The chemical reaction of weak monoprotic acid and KOH follows the equation:
[tex]HA+KOH\rightarrow KA+H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of KOH reacts with 1 mole of weak monoprotic acid.
So, [tex]4.24\times 10^{-3}mol[/tex] of KOH will react with = [tex]\frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol[/tex] of weak monoprotic acid.
Hence, the number of moles of weak acid is [tex]4.24\times 10^{-3}[/tex] moles.
