Answer:
acceleration a= 0.1344 m/sec^2
Explanation:
Given
mass of the object m= 72 kg
Force applied with help of rope= 358 N
Acceleration due to gravity= 9.81 m/sec^2
Since there is no force acting on the person and rope
then T=F
and from the FBD we can write
2T- mg= ma ,or
2F- mg= ma
[tex]a=\frac{2F-mg}{m}[/tex]
now putting the values we get
[tex]a=\frac{2F-mg}{m}[/tex]
[tex]a=\frac{2\times358-72\times9.81}{72}[/tex]
on calculating we get acceleration a= 0.1344 m/sec^2
