Answer:
Step-by-step explanation:
Given that a new restaurant with 138 seats is being planned. Studies show that 59% of the customers demand a smoke-free area.
Non smoke area = 100-59=41%
mu for non smoke area = 0.41
Std deviation = [tex]\sqrt{\frac{pq}{n} } =0.0418[/tex]
mu-3sigma = [tex]0.41-3(0.0418) =0.2843[/tex]
mu+3 sigma = [tex]0.41+3(0.0418)=0.5354[/tex]
Thus 28.43 to 53.54 percent should be in non smoke area
Or 39.2334 to 73.8852 seats
74 seats should be in the non-smoking area in order to be very sure (mu plus 3 sigma) of having enough seating there
