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Water's heat of fusion is 80. cal/g , and its specific heat is 1.0calg⋅∘C . Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held 1900 g of frozen water at 0 ∘C , and the temperature of the water at the end of the ride was 32 ∘C , how many calories of heat energy were absorbed?

Respuesta :

Answer:

212800 cal

Explanation:

we have to find the total heat absorbed

we have given tha

latent heat of fusion = 80 cal/g

mass of frozen water =1900 g

heat absorbed during fusion

[tex]Q=mL=1900\times 80=152000\ cal[/tex]

no heat absorbed during temperature rise from 0°Ct  to 32°C

[tex]Q=mc_pdt=1900\times 1\times (32-0)=60800\ cal[/tex]

so total heat absorbed =152000+60800=212800 cal

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