Respuesta :
Answer:
1822.14 J/kg C
Explanation:
Mass of aluminum = 0.100 kg
Mass of Water = 0.250 kg
Mass of copper = 0.300 kg
Mass of unknown object = 0.70 kg
Initial temperature of Aluminum = 10 C
Initial temperature of water = 10 C
Initial temperature of copper = 30 C
Initial temperature of = 100 C
Final temperature of all substances = 20 C
Change in temperature of each of them Aluminum, water , copper and unknown material respectively = 10 C , 10 C , -10 C, -80 C respectively
Specific heat of each of them Aluminum, water , copper and unknown material respectively = 900,4186,387 and c respectively.
Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j
heat lost by copper and unknown material =(0.3)(387)(-10) = -1161
heat lost by unknown material = (0.070)(c)(-80) = -5.6 c
Now solve for c using the calorimetry principle.
Heat lost + Heat gained = 0
⇒ -5.6 c = -11365 - (-1161) = -10204 j
Specific heat of unknown material = - 10204 / -5.6
= 1822.14 j/kg C
b) Material having a specific heat of 1800 j /kg C is
Polyurethane elastomer.
(a) The specific heat capacity of the unknown sample is 1.82 J/g⁰C.
(b) From the value of the specific heat capacity, the material made of Beryllium.
Specific heat capacity of the unknown sample
The specific heat capacity of the unknown sample is calculated as follows;
Heat lost by the samples = Heat gained by the calorimeter and water
[tex]M_cC_c\Delta \theta_c + M_sC_s\Delta \theta_s = (M_wC_w + M_a_lC_a_l)\Delta \theta[/tex]
300(0.385)(30 - 20) + 70Cs(100 - 20) = (250 x 4.184 + 100 x 0.89)(20 - 10)
1155 + 5600Cs = 11350
5600Cs = 10,195
Cs = 1.82 J/g⁰C
Thus, from the value of the specific heat capacity, the material made of Beryllium.
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