Answer: 0.4987
Step-by-step explanation:
Given : The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with
Mean : [tex]\mu=5\text { lbs}[/tex]
Standard deviation : [tex]\sigma= 2\text{ lbs}[/tex]
Let X be the random variable that represents the weight of randomly selected student .
Z score : [tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x = 5 lbs
[tex]z=\dfrac{5-5}{2}=0[/tex]
For x = 11 lbs
[tex]z=\dfrac{11-5}{2}=3[/tex]
By using the standard normal distribution table , Â the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs :-
[tex]P(5<X<11)=P(0<z<3)=P(z<3)-P(z<0)\\\\=0.9986501-0.5=0.4986501\approx0.4987[/tex]
Hence, the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs =0.4987