Answer:[tex]\lambda =248.99 nm[/tex]
Explanation:
Given
Work function[tex]\left ( \phi \right )=4.98\approx 1.602\times 10^{-19}\times 4.98[/tex]
[tex]h=6.626\times 10^{-34} J[/tex]
[tex]c=2.998\times 10^8[/tex]
[tex]\phi =\frac{hc}{\lambda }[/tex]
[tex]\lambda =\frac{hc}{\phi }[/tex]
[tex]\lambda =\frac{6.626\times 10^{-34}\times 2.998\times 10^8}{4.98\times 1.602\times 10^{-19}} [/tex]
[tex]\lambda =248.99 nm[/tex]