Respuesta :
Answer: The mass of tetraphosphorus decaoxide formed is 64.81g
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
- For potassium chlorate:
Given mass of potassium chlorate = 93.3 g
Molar mass of potassium chlorate = 122.55 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of potassium chlorate}=\frac{93.3g}{122.55g/mol}=0.761mol[/tex]
For the given chemical reaction:
[tex]10KClO_3+12P\rightarrow 3P_4O_{10}+10KCl[/tex]
Red phosphorus is given in excess . So, it is considered as an excess reagent and potassium chlorate is considered as a limiting reagent.
By Stoichiometry of the reaction:
10 moles of potassium chlorate reacts with 3 moles of tetraphosphorus decaoxide
So, 0.761 moles of potassium chlorate will react with = [tex]\frac{3}{10}\times 0.761=0.2283moles[/tex] of tetraphosphorus decaoxide
Calculating the mass of tetraphosphorus decaoxide by using equation 1, we get:
Molar mass of tetraphosphorus decaoxide = 283.886 g/mol
Moles of tetraphosphorus decaoxide = 0.2283 moles
Putting values in equation 1, we get:
[tex]0.2283mol=\frac{\text{Mass of tetraphosphorus decaoxide}}{283.886g/mol}\\\\\text{Mass of tetraphosphorus decaoxide}=64.81g[/tex]
Hence, the mass of tetraphosphorus decaoxide formed is 64.81g
