Respuesta :
Answer:
2,855 is the size of the colony of mosquitoes after 4 days.
Explanation:
The law of uninhibited growth is given as:
[tex]A=A_o\times e^{k\times t}[/tex]
[tex]A_o[/tex]= Original amount
A = Amount after time t
k = Positive constant repressing the rate of growth
We are given with:
Original population of mosquitoes = 1000
Population of mosquitoes after 1 day =1300
t = 1 day
[tex]1300=1000\times e^{k\times 1 day}[/tex]
[tex]k = 0.2623 day^{-1}[/tex]
Population size of mosquitoes after 4 days
[tex]A_o=1000, k= 0.2623 day^{-1}[/tex]
A =? , t = 4 days
[tex]A=1000\times e^{ 0.2623 day^{-1}\times 4 days}[/tex]
A =2,855.36 ≈ 2,855 mosquitoes
2,855 is the size of the colony of mosquitoes after 4 days.
Answer:
[tex]2855[/tex]
Explanation:
As per the law of uninhibited growth
Population after a time period of "t" will be given by
[tex]P(t)= P_0e^{kt}[/tex]
where,
[tex]P_0[/tex] is the initial population.
k is the growth rate
Growth rate of mosquitoes
[tex]1300= 1000*e^{k*1}\\e = 0.2623[/tex]per day
So, population of mosquitoes after four days will be
[tex]= 1000* e^{0.2623*4}\\=1000*2.855 \\= 2855[/tex]
