Answer:B=12.52 T
Explanation:
Given
[tex]r=5.30\times 10^{-11} m[/tex]
[tex]v=2.2\times 10^{6} m/s[/tex]
[tex]q=1.60\times 10^{-19} c[/tex]
[tex]Magnetic field(B)=\frac{\nu _0I}{2r}[/tex]
[tex]B=\frac{\mu _0Q}{2r\times \frac{2\pi r}{v}}[/tex]
[tex]B=\frac{4\pi \times 10^{-7}\times 1.6\times 10^{-19}}{2\times 5.30\times 10^{-11}\times 15.138\times 10^{-17}}[/tex]
B=12.52 T
