Respuesta :
Answer:
distance = 4.67 m
time = 1.44s
speed = 6.48 m/s
Step-by-step explanation:
initial speed v₀ = 6.48 m/s
θ = 27.3⁰
a) distance traveled by the block
[tex]L = \dfrac{v^2}{2gsin \theta}\\L = \dfrac{6.48^2}{2\times 9.8\times sin 27.3^{o}}\\L = 4.67 m[/tex]
b) time taken to travel
[tex]t = \sqrt{\dfrac{2L}{gsin\theta}}\\ t = \sqrt{\dfrac{2\times 4.67}{9.8 \times sin27.3^o}}\\t = 1.44s[/tex]
c) speed at the bottom
h = L sinθ
h = 4.67× sin 27.3°
h = 2.14 m
by law of conservation of energy
[tex]mgh = \dfrac{1}{2}mv^2\\v = \sqrt{{2gh} } \\v = \sqrt{{2\times 9.8\times2.14} }\\v = 6.48 m/s[/tex]
speed equal to 6.48 m/s
