An ice chest contains six cans of apple​ juice, four cans of grape​ juice, five cans of orange​ juice, and eight cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting no grape juice.

Respuesta :

Answer:

[tex]\frac{969}{1771}[/tex]

Step-by-step explanation:

Given,

Cans of apple juice = 6,

Cans of grape juice = 4,

Cans of orange juice = 5,

Cans of mango juice = 8,

Thus, the number of cans with no grape juice = 6 + 5 + 8 = 19,

While the total cans = 6 + 4 + 5 + 8 = 23,

Number of ways of choosing any three cans = [tex]^{23}C_3[/tex]

Number of ways of choosing 3 non grape juice cans = [tex]^{19}C_3[/tex]

Hence, the probability of selecting no grape juice = [tex]\frac{^{19}C_3}{^{23}C_3}[/tex]

[tex]=\frac{\frac{19!}{3!16!}}{\frac{23!}{3!20!}}[/tex]

[tex]=\frac{969}{1771}[/tex]

Q&A Education