Answer:
a = 0.052 m s^{-2}
T = 12185.49 N
Explanation:
from the figure:
determine the Force [tex]F_R = NF_2i = 9*1358 i = 12222 N[/tex]
Determine the force [tex]F_L = NF_1i = 9*1350 i = - 12150ii N[/tex]
by Newton's second law, net force F_net
[tex]F_net = \sum{F_1+ F_2 +...... = ma ........(1)[/tex]
[tex]F_R +F_L = ma[/tex]
12222- 12150 = ma
[tex]a = \frac{ 72}{9(78+73)}[/tex]
a = 0.052 m s^{-2}
B) TENSION T in section of rope
by newton's second law
[tex]F_Ri -Ti = 9m_2ai[/tex]
[tex]T = F_Ri - 9m_2ai[/tex]
T = 12222i - 9*78*0.052
T = 12185.49 N
