Respuesta :
Answer: The molality of the solution is 0.1 m.
Explanation:
To calculate the molality of solution, we use the equation:
[tex]Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}[/tex]
Where,
[tex]m_{solute}[/tex] = Given mass of solute = 27.1 g
[tex]M_{solute}[/tex] = Molar mass of solute = 27.1 g/mol
[tex]W_{solvent}[/tex] = Mass of solvent = 100 g
Putting values in above equation, we get:
[tex]\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m[/tex]
Hence, the molality of the solution is 0.1 m.
Answer:
the molality of the solution is 10 mol/kg
Explanation:
To find the molality of a solution we apply the following formula
[tex]m=\frac{moles of solute}{kg of solvent}[/tex]
data:
100 g of solvente
We have the amount of solvent expressed in grams but to be able to use the data in the formula we must pass it to kilograms
we apply a simple rule of three
[tex]1000 g \longrightarrow 1Kg\\100g \longrightarrow x \\x=\frac{(100)(1)}{1000}\\ x=0.1 Kg[/tex]
27.1g of solute, molar mass 27.1 g/mol
We need the moles of solute and they give us grams of solute and molar mass
The molar mass is 27.1 g / mol This means that there is 27.1 g for each mol of solute.
The amount of solute we have is 27.1g and according to the molar mass this amount of solute corresponds exactly to 1 mole
Therefore having 27.1 g of solute is equivalent to saying that we have 1 mol of solute
Now that we have the data in the correct units we apply the formula
[tex]m=\frac{moles of solute}{kg of solvent}\\m=\frac{1mol}{0.1kg}\\ m=10 \frac{mol}{kg}[/tex]
the molality of the solution is 10 mol/kg
