Suppose that two cards are randomly selected from a standard​ 52-card deck. ​(a) What is the probability that the first card is a club and the second card is a club if the sampling is done without​ replacement? ​(b) What is the probability that the first card is a club and the second card is a club if the sampling is done with​ replacement?

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Answer:

(a) 1/ 17  (b) 1/16.

Step-by-step explanation:

(a) Probability ( first car d is a club) = 13/52 = 1/4

Probability( second card is a club) = 12/51 .

So the probability ( first and second are clubs) = 1/4 * 12/51

= 12/ 204 = 1/17 (answer).

(b)  Probability ( first car d is a club) = 13/52 = 1/4

Probability ( second card is a club) = 13 / 52 = 1/4

So the probability ( first and second are clubs) = 1/4 * 1/4

= 1/16. (answer).

The probability that the first card is a club and the second card is a club if the sampling is done without​ replacement = 0.589

The probability that the first card is a club and the second card is a club if the sampling is done with​ replacement = 0.0625

What is probability?

Probability is simply how likely something is to happen.

A = The first card is a club and the second card is a club if the sampling is done without​ replacement.

When the first card is drawn,

Number of favorable events = Number of clubs = 13

Number of total events = Number of cards = 52

Probability that the first card drawn is a club = [tex]\frac{13}{52}[/tex]

When the second card is drawn without replacement,

Number of favorable events = Number of clubs - 1 = 12

Number of total events = Number of cards - 1 = 51

Probability that the second card is a club =  [tex]\frac{12}{51}[/tex]

P(A) = Probability that the first card is a club * Probability that the second card is club  = [tex]\frac{13}{52}*\frac{12}{51} = 0.059[/tex]

B = The first card is a club and the second card is a club if the sampling is done with​ replacement.

When the first card is drawn,

Number of favorable events = Number of clubs = 13

Number of total events = Number of cards = 52

Probability that the first card drawn is a club = [tex]\frac{13}{52}[/tex]

When the second card is drawn with replacement,

Number of favorable events = Number of clubs = 13

Number of total events = Number of cards = 52

Probability that the second card is a club =  [tex]\frac{13}{52}[/tex]

P(A) = Probability that the first card is a club * Probability that the second card is club  = [tex]\frac{13}{52}*\frac{13}{52} = 0.0625[/tex]

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