Calculate the change in entropy that occurs in the system when 3.10 mole of isopropyl alcohol (C3H8O) melts at its melting point (-89.5∘C). ΔH∘fus = 5.37 kJ/mol

Respuesta :

Answer:

ΔS = 0.0906 kJ/K

Explanation:

The entropy of a reversible process is the amount of heat energy absorbed in the process divided by the temperature in degree Kelvin. Mathematically,

ΔS = Q/T

Where:

ΔS = change in entropy (kJ/K)

Q = is the amount of heat energy absorbed (kJ)

T = Temperature of the system (K)

Thus, the change in entropy that occurs in the system when 3.10 mole of isopropyl alcohol melts at its melting point (-89.5∘C) is calculated as shown below:

Q = 3.10 mol * 5.37 kJ/mol = 16.647 kJ

T = -89.5 + 273.15 = 183.65 K

Therefore,

ΔS = Q/T = 16.647 kJ/183.65 K = 0.0906 kJ/K

The change in the entropy that occurs in the system is 0.09 KJ/K

Determination of the heat of the reaction

•Number of mole (n) = 3.10 moles

•Heat of fusion (ΔHf) = 5.37 KJ/mol

•Heat (Q) =?

Q = n•ΔHf

Q = 3.1 × 5.37

Q = 16.647 KJ

Determination of the change in entropy

•Heat (Q) = 16.647 KJ

•Temperature (T) = -89.5 °C = -89.5 + 273 = 183.5 K

•Change in entropy (ΔS) =?

ΔS = Q / T

ΔS = 16.647 / 183.5

ΔS = 0.09 KJ/K

Thus, the change in the entropy of system is 0.09 KJ/K

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