Respuesta :
Answer:
ΔS = 0.0906 kJ/K
Explanation:
The entropy of a reversible process is the amount of heat energy absorbed in the process divided by the temperature in degree Kelvin. Mathematically,
ΔS = Q/T
Where:
ΔS = change in entropy (kJ/K)
Q = is the amount of heat energy absorbed (kJ)
T = Temperature of the system (K)
Thus, the change in entropy that occurs in the system when 3.10 mole of isopropyl alcohol melts at its melting point (-89.5∘C) is calculated as shown below:
Q = 3.10 mol * 5.37 kJ/mol = 16.647 kJ
T = -89.5 + 273.15 = 183.65 K
Therefore,
ΔS = Q/T = 16.647 kJ/183.65 K = 0.0906 kJ/K
The change in the entropy that occurs in the system is 0.09 KJ/K
Determination of the heat of the reaction
•Number of mole (n) = 3.10 moles
•Heat of fusion (ΔHf) = 5.37 KJ/mol
•Heat (Q) =?
Q = n•ΔHf
Q = 3.1 × 5.37
Q = 16.647 KJ
Determination of the change in entropy
•Heat (Q) = 16.647 KJ
•Temperature (T) = -89.5 °C = -89.5 + 273 = 183.5 K
•Change in entropy (ΔS) =?
ΔS = Q / T
ΔS = 16.647 / 183.5
ΔS = 0.09 KJ/K
Thus, the change in the entropy of system is 0.09 KJ/K
Learn more about entropy:
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