Answer: The volume of [tex]H_2SO_4[/tex] comes out to be 10.2625 mL.
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is KOH.
We are given:
[tex]n_1=2\\M_1=0.100M\\V_1=?mL\\n_2=1\\M_2=0.0821M\\V_2=25mL[/tex]
Putting values in above equation, we get:
[tex]2\times 0.100\times V_1=1\times 0.0821\times 25\\\\V_1=10.2625mL[/tex]
Hence, the volume of [tex]H_2SO_4[/tex] comes out to be 10.2625 mL.
