Answer:
t = 1.51 s
Explanation:
Initial position of the particle is given as
[tex]r_1[/tex] = (8m, 0m)
now the velocity is initially along - Y direction so it is given as
[tex]v_i = - 3\hat j[/tex]
now we know that the acceleration of the particle is given as
[tex]\vec a = -3.5 \hat i + 6 \hat j[/tex]
now when particle will cross Y axis then the displacement in x direction is given as
[tex]d_x = 0 - 8 = - 8m[/tex]
so in x direction we can use kinematics as
[tex]d_x = v_{ix} t + \frac{1}{2} at^2[/tex]
[tex]- 8 = 0 + (-3.5) t^2[/tex]
[tex]t = 1.51 s[/tex]
