Respuesta :
Answer: The total number of moles of gases produced are 7.25 moles.
Explanation:
The chemical reaction for the decomposition of [tex]C_3H_5(NO_3)_3[/tex] follows the equation:
[tex]4C_3H_5(NO_3)_3\rightarrow 12CO_2(g)+6N_2(g)+10H_2O(g)+O_2(g)[/tex]
We are given:
Moles of [tex]C_3H_5(NO_3)_3[/tex] = 1.00 mol
- For carbon dioxide:
By Stoichiometry of the reaction:
4 moles of [tex]C_3H_5(NO_3)_3[/tex] is producing 12 moles of carbon dioxide.
So, 1 mole of [tex]C_3H_5(NO_3)_3[/tex] will produce = [tex]\frac{12}{4}\times 1=3mol[/tex] of carbon dioxide.
Moles of carbon dioxide produced = 3 moles
- For nitrogen:
By Stoichiometry of the reaction:
4 moles of [tex]C_3H_5(NO_3)_3[/tex] is producing 6 moles of nitrogen.
So, 1 mole of [tex]C_3H_5(NO_3)_3[/tex] will produce = [tex]\frac{6}{4}\times 1=1.5mol[/tex] of nitrogen.
Moles of nitrogen produced = 1.5 moles
- For water:
By Stoichiometry of the reaction:
4 moles of [tex]C_3H_5(NO_3)_3[/tex] is producing 10 moles of water.
So, 1 mole of [tex]C_3H_5(NO_3)_3[/tex] will produce = [tex]\frac{12}{10}\times 1=2.5mol[/tex] of water.
Moles of water produced = 2.5 moles
- For oxygen:
By Stoichiometry of the reaction:
4 moles of [tex]C_3H_5(NO_3)_3[/tex] is producing 1 moles of oxygen.
So, 1 mole of [tex]C_3H_5(NO_3)_3[/tex] will produce = [tex]\frac{1}{4}\times 1=0.25mol[/tex] of oxygen.
Moles of oxygen produced = 0.25 moles
Total number of moles of the gases produced are = 3 + 1.5 + 2.5 + 0.25 = 7.25 moles.
Hence, the total number of moles of gases produced are 7.25 moles.
