Determine the volume at the equivalence point if a 0.100 M NaOH(aq) solution is used to titrate the following acidic solutions: (a) 50.0 mL of 0.200 M HBr(aq) (b) 30.0 mL of 0.150 M HNO3(aq)

Respuesta :

Answer:

a) NaOH volume at the equivalence point is 100 ml.

b) NaOH volume at the equivalence point is 45 ml.

Explanation:

To calculate the concentration of acid, we use the equation given y neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid.

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base

a) If a 0.100 M NaOH (aq) solution is used to titrated with 50.0 mL of 0.200 M HBr(aq).

We are given:

[tex]n_1=1\\M_1=0.200M\\V_1=50.0mL\\n_2=1\\M_2=0.100M\\V_2=?mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.200M\times 50.0 mL=1\times 0.100 M\times V_2\\\\V_2=100 mL[/tex]

b) If a 0.100 M NaOH (aq) solution is used to titrated with 30.0 mL of 0.150 M [tex]HNO_3[/tex](aq).

We are given:

[tex]n_1=1\\M_1=0.150M\\V_1=30.0mL\\n_2=1\\M_2=0.100M\\V_2=?mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.150M\times 30.0 mL=1\times 0.100 M\times V_2\\\\V_2=45 mL[/tex]

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