Answer: 0.58 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]V_s[/tex] = volume of solution in ml
Given : 10.2 g of glucose is present in 100 g of solution
density of solution = 1.03 g/ml
volume of solution =[tex]\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.03g/ml}=97.1ml[/tex]
[tex]{\text {moles of solute}}=\frac{\text {given mass}}{\text {molar mass}}=\frac{10.2g}{180g/mol}=0.057moles[/tex]
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.057moles\times 1000}{97.1ml}=0.58mole/L[/tex]
Thus the molarity of solution will be 0.58 M.
