Explanation:
It is given that,
Mass of the truck, m = 2000 kg
Initial velocity of the truck, u = 34 km/h = 9.44 m/s
Final velocity of the truck, v = 58 km/h = 16.11 m/s
(a) Change in truck's kinetic energy, [tex]\Delta E=\dfrac{1}{2}m(v^2-u^2)[/tex]
[tex]\Delta E=\dfrac{1}{2}\times 2000\ kg\times (16.11^2-9.44^2)[/tex]
[tex]\Delta E=170418.5\ J[/tex]
[tex]\Delta E=1.7\times 10^5\ J[/tex]
(b) Change in momentum of the truck, [tex]\Delta p=m(v-u)[/tex]
[tex]\Delta p=2000\ kg\times (16.11-9.44)[/tex]
[tex]\Delta p=13340\ kg-m/s[/tex]
Hence, this is the required solution.
