A cylinder contains a mixture of helium and argon gas in equilibrium at a temperature of 233◦ C. The value of Boltzmann’s constant is 1.38066 × 10−23 J/K, and Avogadro’s number is 6.02 × 1023 mol−1. What is the average kinetic energy of each type of molecule? Answer in units of J.

Respuesta :

Answer : The average kinetic energy is, [tex]1.04742\times 10^{-20}J[/tex]

Explanation :

The formula for average kinetic energy is:

[tex]K.E=\frac{3}{2}kT[/tex]

where,

k = Boltzmann’s constant = [tex]1.38066\times 10^{-23}J/K[/tex]

T = temperature = [tex]233^oC=273+233=506K[/tex]

Now put all the given values in the above average kinetic energy formula, we get:

[tex]K.E=\frac{3}{2}\times (1.38\times 10^{-23}J/K)\times (506K)[/tex]

[tex]K.E=1.04742\times 10^{-20}J[/tex]

Therefore, the average kinetic energy is, [tex]1.04742\times 10^{-20}J[/tex]

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