Identify the oxidizing agent and the reducing agent for the following reaction: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s) Express your answers as chemical formulas separated by a comma.

Respuesta :

Answer: oxidizing agent: [tex]Cu^{2+}[/tex], reducing agent :[tex]Zn[/tex]

Explanation: Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

For the given reaction:

[tex]Zn(s)+Cu^{2+}(aq)\rightarrow Zn^{2+}(aq)+Cu(s)[/tex]

On reactant side:

Oxidation state of zinc = 0

Oxidation state of copper = +2

On product side:

Oxidation state of zinc = +2

Oxidation state of copper = 0

The oxidation state of copper reduces from +2 to 0, it is getting reduced. The substance which itself gets reduced, oxidizes other and is called as oxidizing agent.Thus [tex]Cu^{2+}[/tex] acts as oxidizing agent.

The oxidation state of zinc increases from 0 to +2. Thus, it is getting oxidized and it undergoes oxidation reaction. The substance which itself gets oxidized, reduces other and is called as reducing agent.Thus [tex]Zn[/tex] acts as reducing agent.

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