Explanation:
We need to calculate the speed of light in each materials
(I). Gallium phosphide,
The index of refraction of Gallium phosphide is 3.50
Using formula of speed of light
[tex]v=\dfrac{c}{\mu}[/tex]....(I)
Where, [tex]\mu[/tex] = index of refraction
c = speed of light
Put the value into the formula
[tex]v=\dfrac{3\times10^{8}}{3.50}[/tex]
[tex]v=8.6\times10^{7}\ m/s[/tex]
(II) Carbon disulfide,
The index of refraction of Gallium phosphide is 1.63
Put the value in the equation (I)
[tex]v=\dfrac{3\times10^{8}}{1.63}[/tex]
[tex]v=1.8\times10^{8}\ m/s[/tex]
(III). Benzene,
The index of refraction of Gallium phosphide is 1.50
Put the value in the equation (I)
[tex]v=\dfrac{3\times10^{8}}{1.50}[/tex]
[tex]v=2\times10^{8}\ m/s[/tex]
Hence, This is the required solution.
