Answer:
6.3445×10⁻¹⁶ m
Explanation:
E = Accelerating voltage = 2.47×10³ V
m = Mass of electron
Distance electron travels = 33.5 cm = 0.335 cm
[tex]E=\frac{mv^2}{2}\\\Rightarrow v=\sqrt{\frac{2E}{m}}\\\Rightarrow v=\sqrt{\frac{2\times 2470\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=29455356.08671\ m/s[/tex]
Deflection by Earth's Gravity
[tex]\Delta =\frac {gt^2}{2}[/tex]
Now, Time = Distance/Velocity
[tex]\Delta =\frac {g\frac{s^2}{v^2}}{2}\\\Rightarrow \Delta =\frac{9.81\frac{0.335^2}{29455356.08671^2}}{2}\\\Rightarrow \Delta =6.3445\times 10^{-16}\ m[/tex]
∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m
