Answer:
The new pressure in the holding tank is 2 atm.
Explanation:
Given that,
Volume = 10000 L
Initial pressure 2 atm
Initial temperature = 300 k
We need to calculate the new pressure
Using equation of ideal gas
[tex]PV=RT[/tex]
[tex]R=\dfrac{PV}{T}[/tex]
Where,P = pressure
T = temperature
V = volume
R = constant
Put the value into the formula
Volume of gas are remain constant
So,
[tex]\dfrac{P_{i}V}{T_{i}}=\dfrac{P_{f}V}{T_{f}}[/tex]
[tex]\dfrac{2\times10000}{300}=\dfrac{P_{f}\times10000}{300}[/tex]
[tex]P_{f}=2\ atm[/tex]
Hence, The new pressure in the holding tank is 2 atm.
