Answer:
The amount invested in account that paid 4% was $2,400
The amount invested in account that paid 9% was $1.600
Step-by-step explanation:
Let
x -----> amount invested in account that paid 4%
(4,000-x) -----> amount invested in account that paid 9%
we know that
The linear equation that represent this scenario is
[tex]x(0.04)+(4,000-x)(0.09)=4,000(0.06)[/tex]
Solve for x
[tex]0.04x+360-0.09x=240[/tex]
[tex]0.09x-0.04x=360-240[/tex]
[tex]0.05x=120[/tex]
[tex]x=\$2,400[/tex]
[tex](4,000-x)=4,000-2,400=\$1,600[/tex]
therefore
The amount invested in account that paid 4% was $2,400
The amount invested in account that paid 9% was $1.600
