A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 turns through 2.4 revolutions during a 2.0-s time interval. What is the angular velocity at the end of this time interval

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Answer:

Explanation:

from equation of motion

[tex]s = ut + \frac{1}{2}at^2[/tex]

[tex]2.4*2\pi = u*2+\frac{1}{2}*2*4[/tex]

u = 5.53 rad/sec

we know that from equation of motion , angular velocity is obtained as

v =u +at

v =5.53 + 2*2

v = 9.536 rad/sec

This question involves the concepts of the equations of motion and angular motion.

The angular velocity at the end of the time interval will be "4 rad/s".

Final Angular Velocity

The final angular velocity can be found using the first equation of motion for angular motion, as follows:

[tex]\omega_f=\omega_i + \alpha t[/tex]

where,

  • [tex]\omega_f[/tex] = final angular velocity = ?
  • [tex]\omega_i[/tex] = initial angular velocity = 0 rad/s
  • [tex]\alpha[/tex] = angular acceleration = 2 rad/s²
  • t = time interval = 2 s

Therefore,

[tex]\omega_f=0\ rad/s+(2\ rad/s^2)(2\ s)\\\omega_f=4\ rad/s[/tex]

Learn more about the equations of motion here:

https://brainly.com/question/5955789

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