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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
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Input the equation of the given line in standard form.
The line including (3, 1) and (-2, 3).

Respuesta :

matthewalex2005

Answer:

10x + 5y = 11

Step-by-step explanation:

I usually find it in slope intercept then convert, it's easier for me.

First you find slope using delta y over delta x giving you -2/5.

so you have y=-2/5x + b

To find b plug in a point and solve down

1 = -2/5(3) +b

1+6/5 = b

b = 11/5

y=-2/5x + 11/5

Then you convert it to Ax+by=C form,

multiply by 5

5y = -10x + 11

move x

10x +5y = 11

Answer:

[tex]2x+5y-11 =0[/tex]

Step-by-step explanation:

Givens

Coordinates [tex](3,1)[/tex] and [tex](-2,3)[/tex]

We need to find the equation of the line that passes through those points.

First, we have to find its slope with the following formula

[tex]m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]

We replace the given points

[tex]m=\frac{3-1}{-2-3}=\frac{2}{-5}[/tex]

Now, we use the point-slope formula to find the equation

[tex]y-y_{1} =m(x-x_{1} )\\y-1=-\frac{2}{5}(x-3)\\ y-1=-\frac{2}{5}x +\frac{6}{5}\\ y+\frac{2}{5}x-\frac{6}{5}-1=0\\\frac{2}{5}x+y-\frac{11}{5} =0[/tex]

But, the standard form is [tex]Ax+By+C=0[/tex]

So, if we multiply the equation by 5, we would have a better representation

[tex]2x+5y-11 =0[/tex]

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