Answer:
T_f = 24.32 degree celcius
Explanation:
given details:
Q = 6279 kJ/day
V = 25 gal
T = 23°C
we know that heat released can be written as
[tex]Q = m*Cp*(T_f -T_i)[/tex]
Q = 6279 kJ/24 h *2h = 523.25 kJ
V = 25 gal = 94.6353 l tr
density of water is 1 kg/cm3
so, m = 94.65 kg
then
523.25 = 94.65*4.18* (T_f - 23)
T_f = 24.32°C