Respuesta :
Answer:
B = 32.17 x 10^-8 Tesla
u = 8.24 x 10^-8 J/m^3
P/A = 24.72 W/m^2
Explanation:
E = 96.5 V/m
velocity of light, c = 3 x 10^8 m/s
Let B be the magnetic field.
The relation between the electric field strength and the magnetic field strength is given by
B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla
Let u be the energy density.
[tex]u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}[/tex]
[tex]u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}[/tex]
u = 8.24 x 10^-8 J/m^3
Let Power flow per unit area is
P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2
