Answer:
The the maximum emf is [tex]2.52\times10^{-11}\ V[/tex]
Explanation:
Given that,
Magnetic field [tex]B = 1.40\times10^{-3}\ T[/tex]
Frequency = 60 Hz
Diameter = 7.8 μm
We need to calculate the maximum emf
Using formula of emf
[tex]\epsilon=NBA\omega[/tex]
Where, N = number of turns
B= magnetic field
A = area
Put the value in to the formula
[tex]\epsilon=1\times1.40\times10^{-3}\times\pi\times(\dfrac{7.8\times10^{-6}}{2})^2\times2\times\pi\times60[/tex]
[tex]\epsilon=2.52\times10^{-11}\ V[/tex]
Hence, The the maximum emf is [tex]2.52\times10^{-11}\ V[/tex]