Answer with explanation:
Sample Size=322
Success=270
Probability of Success(p)
[tex]=\frac{270}{322}\\\\=\frac{135}{161}[/tex]
At 98% confidence interval , population proportion will be
[tex]=z_{98 \text{Percent}}\times \sqrt{\frac{p(1-p)}{n}}\\\\=0.8365 \times\sqrt{\frac{\frac{270}{322}(1-\frac{270}{322})}{322}}\\\\=0.8365 \times\sqrt{\frac{\frac{270}{322}\times(\frac{52}{322})}{322}}\\\\=\frac{0.8365}{322} \times \sqrt{270 \times 52}\\\\=0.00259782 \times \sqrt{14040}\\\\=0.00259782 \times 118.490\\\\=0.307817[/tex]
= 0.308( approx to three decimal places.)
