A person who eats 3040 Cal each day consumes 1.27254 × 107 J of energy in a day. How much water at 100◦C could that much energy vaporize? The latent heat of vaporization of water is 2.26 × 106 J/

Respuesta :

Answer:

5.63 gram

Explanation:

As per the equation

Q = Lm

where Q is the amount of heat needed to convert water in to vapour

and L is the latent heat f vaporization.

m is the mass converted, hence putting all the values.

m =Q/L

   =  12725400/ 2260000

   = 5.63 gram

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