Answer:
9
Step-by-step explanation:
we are rolling two die until we get minimum of 5 in two die
we get (5,5) (5,6) (6,5) (6,6)
total number of sample space =36 as two die is rolled
so the probability of the event [tex]p=\frac{4}{36}=\frac{1}{9}[/tex]
so [tex]p\left ( X=x \right )=\frac{4}{36}\left ( 1-\frac{4}{36} \right )^{x-1}[/tex]
where x=1,2,3,4--------------
[tex]=\sum \frac{1}{9}\times (1-\frac{4}{36})^{x-1}x[/tex]
[tex]=\frac{1}{9}\left ( 1-\overline{1-\frac{1}{9}} \right )^{-2}=\frac{36}{4}=9[/tex]
