Two long parallel wires, each carrying a current of 2 A, lie a distance 25 cm from each other. If the distance between the wires is tripled, (a) by what multiplicative factor is the force per unit length changed?

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aristocles aristocles · Answer 1 · 2019-08-08T02:15:05+02:00

Answer:

the force will become 1/3 times the initial force

Explanation:

As we know that force between two current carrying wires is given by the formula

[tex]F = \frac{\mu_0 i_1 i_2 L}{2\pi d}[/tex]

here we know that

[tex]i_1, i_2[/tex] = currents flowing in two wires

L = length of the wire on which force is to be calculated

d = distance between two wires

now let say the distance between the wires is "d"

so the force between the wires will F1

[tex]F_1 = \frac{\mu_0 i_1 i_2 L}{2\pi d}[/tex]

now the distance is increased by factor of 3

so the force between the wires is given as

[tex]F_2 = \frac{\mu_0 i_1 i_2 L}{2\pi (3d)}[/tex]

so here we can say that the new force between two wires is decreased by factor of 3

so the force will become 1/3 times the initial force