Answer:
4.8 A
Explanation:
We have given phase voltage that is 480 volt
We know that for transformer [tex]\frac{v_1}{v_2}=\frac{N_1}{N_2}[/tex] where [tex]v_1\ and \ v_2[/tex] are phase voltage and [tex]N_1\ and\ N_2[/tex] are primary and secondary turns respectively
We have given 480 v as phase voltage
So [tex]\frac{480}{v_2}=\frac{2}{1}[/tex]
[tex]v_2=240 v[/tex]
We have given that [tex]z_{phase}=50\ ohm[/tex]
so current through each load resistor that phase current [tex]i=\frac{v_{phase}}{z_{phase}}=\frac{240}{50}=4.8\ A[/tex]
