Answer:
[tex]N_{2}[/tex]=20 turns
Explanation:
The given case is a step down transformer as we need to reduce 120 V to 6 V.
number of turns on primary coil N_{P}= 400
current delivered by secondary coil I_{S}= 500 mA
output voltage = 6 V (rms)
we know that
[tex]I_{p}=\frac{V_{out}}{V_{in}\times I_{s}}[/tex]
putting values we get
[tex]I_{p}=\frac{6}{120\times 0.5}[/tex]
[tex]I_{p}= 0.1 A[/tex]
to calculate number of turns in secondary
[tex]\frac{N_{2}}{400} =\frac{6}{120}[/tex]
therefore, [tex]N_{2}[/tex]=20 turns
